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145314121 = 355740853
BaseRepresentation
bin10001010100101…
…01000101001001
3101010102201111111
420222111011021
5244200022441
622230330321
73413102221
oct1052250511
9333381444
10145314121
1175031717
12407b99a1
132414b0b4
1415429081
15cb56081
hex8a95149

145314121 has 4 divisors (see below), whose sum is σ = 145358532. Its totient is φ = 145269712.

The previous prime is 145314107. The next prime is 145314131. The reversal of 145314121 is 121413541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 121413541 = 177141973.

It can be written as a sum of positive squares in 2 ways, for example, as 93315600 + 51998521 = 9660^2 + 7211^2 .

It is a cyclic number.

It is not a de Polignac number, because 145314121 - 213 = 145305929 is a prime.

It is a super-2 number, since 2×1453141212 = 42232387524005282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145314092 and 145314101.

It is not an unprimeable number, because it can be changed into a prime (145314131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16870 + ... + 23983.

It is an arithmetic number, because the mean of its divisors is an integer number (36339633).

Almost surely, 2145314121 is an apocalyptic number.

It is an amenable number.

145314121 is a deficient number, since it is larger than the sum of its proper divisors (44411).

145314121 is an equidigital number, since it uses as much as digits as its factorization.

145314121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44410.

The product of its digits is 480, while the sum is 22.

The square root of 145314121 is about 12054.6306870016. The cubic root of 145314121 is about 525.7378842666.

Adding to 145314121 its reverse (121413541), we get a palindrome (266727662).

It can be divided in two parts, 14 and 5314121, that added together give a palindrome (5314135).

The spelling of 145314121 in words is "one hundred forty-five million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3557 40853 145314121