Base | Representation |
---|---|
bin | 11011000100010110… |
… | …10000111100011100 |
3 | 1101111202120012121200 |
4 | 31202023100330130 |
5 | 214230144201134 |
6 | 10401555355500 |
7 | 1023055102131 |
oct | 154213207434 |
9 | 41452505550 |
10 | 14532022044 |
11 | 6187a47281 |
12 | 29968b2b90 |
13 | 14a78c6417 |
14 | 9bc006588 |
15 | 5a0bc4499 |
hex | 3622d0f1c |
14532022044 has 36 divisors (see below), whose sum is σ = 36739313520. Its totient is φ = 4843270080.
The previous prime is 14532022013. The next prime is 14532022051. The reversal of 14532022044 is 44022023541.
14532022044 is a `hidden beast` number, since 1 + 453 + 2 + 0 + 2 + 204 + 4 = 666.
It is a tau number, because it is divible by the number of its divisors (36).
It is a super-2 number, since 2×145320220442 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14532021999 and 14532022017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 242337 + ... + 296295.
Almost surely, 214532022044 is an apocalyptic number.
It is an amenable number.
14532022044 is an abundant number, since it is smaller than the sum of its proper divisors (22207291476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14532022044 is a wasteful number, since it uses less digits than its factorization.
14532022044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61450 (or 61445 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 27.
Adding to 14532022044 its reverse (44022023541), we get a palindrome (58554045585).
The spelling of 14532022044 in words is "fourteen billion, five hundred thirty-two million, twenty-two thousand, forty-four".
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