145400040541 has 4 divisors (see below), whose sum is σ = 166171474912. Its totient is φ = 124628606172.

The previous prime is 145400040431. The next prime is 145400040589. The reversal of 145400040541 is 145040004541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 145400040541 - 2²¹ = 145397943389 is a prime.

It is a super-2 number, since 2×145400040541² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145400040041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10385717175 + ... + 10385717188.

It is an arithmetic number, because the mean of its divisors is an integer number (41542868728).

Almost surely, 2^145400040541 is an apocalyptic number.

It is an amenable number.

145400040541 is a deficient number, since it is larger than the sum of its proper divisors (20771434371).

145400040541 is an equidigital number, since it uses as much as digits as its factorization.

145400040541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20771434370.

The product of its (nonzero) digits is 6400, while the sum is 28.

The spelling of 145400040541 in words is "one hundred forty-five billion, four hundred million, forty thousand, five hundred forty-one".