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145401341255 = 5259131122227
BaseRepresentation
bin1000011101101010011…
…0000110010101000111
3111220022021021110000022
42013122212012111013
54340240220410010
6150444011205355
713335116002622
oct2073246062507
9456267243008
10145401341255
11567342a2835
122421a74685b
1310932911801
147074b22db9
153bb0003d55
hex21da986547

145401341255 has 8 divisors (see below), whose sum is σ = 174488498352. Its totient is φ = 116316480448.

The previous prime is 145401341243. The next prime is 145401341269. The reversal of 145401341255 is 552143104541.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145401341255 - 28 = 145401340999 is a prime.

It is a super-2 number, since 2×1454013412552 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431549 + ... + 690678.

It is an arithmetic number, because the mean of its divisors is an integer number (21811062294).

Almost surely, 2145401341255 is an apocalyptic number.

145401341255 is a deficient number, since it is larger than the sum of its proper divisors (29087157097).

145401341255 is a wasteful number, since it uses less digits than its factorization.

145401341255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1148145.

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 145401341255 its reverse (552143104541), we get a palindrome (697544445796).

The spelling of 145401341255 in words is "one hundred forty-five billion, four hundred one million, three hundred forty-one thousand, two hundred fifty-five".

Divisors: 1 5 25913 129565 1122227 5611135 29080268251 145401341255