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14540340043 = 83207174749
BaseRepresentation
bin11011000101010101…
…11111101101001011
31101112100012210202201
431202222333231023
5214234311340133
610402453541031
71023215564635
oct154252775513
941470183681
1014540340043
116191708759
122999644777
1314a9549508
149bd16da55
155a17b8d7d
hex362abfb4b

14540340043 has 4 divisors (see below), whose sum is σ = 14540598000. Its totient is φ = 14540082088.

The previous prime is 14540340029. The next prime is 14540340127. The reversal of 14540340043 is 34004304541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14540340043 is a prime.

It is a super-2 number, since 2×145403400432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14540339993 and 14540340020.

It is not an unprimeable number, because it can be changed into a prime (14540340013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4168 + ... + 170581.

It is an arithmetic number, because the mean of its divisors is an integer number (3635149500).

Almost surely, 214540340043 is an apocalyptic number.

14540340043 is a deficient number, since it is larger than the sum of its proper divisors (257957).

14540340043 is an equidigital number, since it uses as much as digits as its factorization.

14540340043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257956.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 14540340043 its reverse (34004304541), we get a palindrome (48544644584).

The spelling of 14540340043 in words is "fourteen billion, five hundred forty million, three hundred forty thousand, forty-three".

Divisors: 1 83207 174749 14540340043