Base | Representation |
---|---|
bin | 1101001110010111001011… |
… | …0111000111011101011111 |
3 | 1220111001021212120202010020 |
4 | 3103211302313013131133 |
5 | 3401212210141114223 |
6 | 50531432533043223 |
7 | 3030336311126250 |
oct | 323456267073537 |
9 | 56431255522106 |
10 | 14540391348063 |
11 | 46a65aa937779 |
12 | 176a037786513 |
13 | 8161cb256779 |
14 | 383a89c10b27 |
15 | 1a3367a6d1e3 |
hex | d3972dc775f |
14540391348063 has 64 divisors (see below), whose sum is σ = 22663494696960. Its totient is φ = 8120942121600.
The previous prime is 14540391348061. The next prime is 14540391348089. The reversal of 14540391348063 is 36084319304541.
It is not a de Polignac number, because 14540391348063 - 21 = 14540391348061 is a prime.
It is a super-2 number, since 2×145403913480632 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14540391347997 and 14540391348015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14540391348061) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 104469148 + ... + 104608238.
It is an arithmetic number, because the mean of its divisors is an integer number (354117104640).
Almost surely, 214540391348063 is an apocalyptic number.
14540391348063 is a deficient number, since it is larger than the sum of its proper divisors (8123103348897).
14540391348063 is a wasteful number, since it uses less digits than its factorization.
14540391348063 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139748.
The product of its (nonzero) digits is 3732480, while the sum is 51.
The spelling of 14540391348063 in words is "fourteen trillion, five hundred forty billion, three hundred ninety-one million, three hundred forty-eight thousand, sixty-three".
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