Base | Representation |
---|---|
bin | 100001000011111011010101… |
… | …111111111000011011100000 |
3 | 201001211121210020200122010120 |
4 | 201003323111333320123200 |
5 | 123024310241230211000 |
6 | 1233130154042000240 |
7 | 42425123454564210 |
oct | 4103732577703340 |
9 | 631747706618116 |
10 | 145405413132000 |
11 | 423700a900230a |
12 | 143846627a6080 |
13 | 6319896730488 |
14 | 27c9933b1a240 |
15 | 11c24dd9676a0 |
hex | 843ed5ff86e0 |
145405413132000 has 1536 divisors, whose sum is σ = 604532765491200. Its totient is φ = 29768778547200.
The previous prime is 145405413131987. The next prime is 145405413132121. The reversal of 145405413132000 is 231314504541.
It is a super-2 number, since 2×1454054131320002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 6535944877 + ... + 6535967123.
It is an arithmetic number, because the mean of its divisors is an integer number (393576019200).
Almost surely, 2145405413132000 is an apocalyptic number.
145405413132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 145405413132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (302266382745600).
145405413132000 is an abundant number, since it is smaller than the sum of its proper divisors (459127352359200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
145405413132000 is a wasteful number, since it uses less digits than its factorization.
145405413132000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22521 (or 22503 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 145405413132000 its reverse (231314504541), we get a palindrome (145636727636541).
The spelling of 145405413132000 in words is "one hundred forty-five trillion, four hundred five billion, four hundred thirteen million, one hundred thirty-two thousand".
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