Base | Representation |
---|---|
bin | 10101001010010000011… |
… | …001010111010001000111 |
3 | 12011000100020011120111102 |
4 | 111022100121113101013 |
5 | 142311020101422210 |
6 | 3032003022330315 |
7 | 210025325634530 |
oct | 25122031272107 |
9 | 5130306146442 |
10 | 1454121514055 |
11 | 51076475a901 |
12 | 1b599a42999b |
13 | a717a5023c2 |
14 | 50546481687 |
15 | 27c5977dea5 |
hex | 15290657447 |
1454121514055 has 64 divisors (see below), whose sum is σ = 2033544683520. Its totient is φ = 977620560000.
The previous prime is 1454121514051. The next prime is 1454121514081. The reversal of 1454121514055 is 5504151214541.
It is not a de Polignac number, because 1454121514055 - 22 = 1454121514051 is a prime.
It is a super-2 number, since 2×14541215140552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1454121514051) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 515827436 + ... + 515830254.
It is an arithmetic number, because the mean of its divisors is an integer number (31774135680).
Almost surely, 21454121514055 is an apocalyptic number.
1454121514055 is a deficient number, since it is larger than the sum of its proper divisors (579423169465).
1454121514055 is a wasteful number, since it uses less digits than its factorization.
1454121514055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3980.
The product of its (nonzero) digits is 80000, while the sum is 38.
Adding to 1454121514055 its reverse (5504151214541), we get a palindrome (6958272728596).
The spelling of 1454121514055 in words is "one trillion, four hundred fifty-four billion, one hundred twenty-one million, five hundred fourteen thousand, fifty-five".
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