Base | Representation |
---|---|
bin | 1000011101101101001… |
… | …1000101101011000000 |
3 | 111220100002110122001011 |
4 | 2013123103011223000 |
5 | 4340301230310130 |
6 | 150445112050304 |
7 | 13335321153055 |
oct | 2073323055300 |
9 | 456302418034 |
10 | 145413135040 |
11 | 5673aa18668 |
12 | 24222693994 |
13 | 109351b0994 |
14 | 707651302c |
15 | 3bb108352a |
hex | 21db4c5ac0 |
145413135040 has 56 divisors (see below), whose sum is σ = 346312705392. Its totient is φ = 58157245440.
The previous prime is 145413135019. The next prime is 145413135067. The reversal of 145413135040 is 40531314541.
It is a super-2 number, since 2×1454131350402 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 145413134993 and 145413135011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2656750 + ... + 2710930.
Almost surely, 2145413135040 is an apocalyptic number.
145413135040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
145413135040 is an abundant number, since it is smaller than the sum of its proper divisors (200899570352).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
145413135040 is an equidigital number, since it uses as much as digits as its factorization.
145413135040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62585 (or 62575 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 145413135040 its reverse (40531314541), we get a palindrome (185944449581).
The spelling of 145413135040 in words is "one hundred forty-five billion, four hundred thirteen million, one hundred thirty-five thousand, forty".
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