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146213630051300 = 22527229839516337
BaseRepresentation
bin100001001111101100000011…
…011110110000001111100100
3201011200212221021102010100122
4201033230003132300033210
5123131031003243120200
61234545340411301112
742540405025212200
oct4117540336601744
9634625837363318
10146213630051300
11426519414230a9
1214495220a4a798
136377b69b4c376
142816ac5493b00
1511d8543302385
hex84fb037b03e4

146213630051300 has 54 divisors (see below), whose sum is σ = 369084977584722. Its totient is φ = 50130387444480.

The previous prime is 146213630051263. The next prime is 146213630051341. The reversal of 146213630051300 is 3150036312641.

146213630051300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 5644957831744 + 140568672219556 = 2375912^2 + 11856166^2 .

It is a super-2 number, since 2×1462136300513002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 14919753269 + ... + 14919763068.

Almost surely, 2146213630051300 is an apocalyptic number.

146213630051300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

146213630051300 is an abundant number, since it is smaller than the sum of its proper divisors (222871347533422).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

146213630051300 is a wasteful number, since it uses less digits than its factorization.

146213630051300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29839516365 (or 29839516351 counting only the distinct ones).

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 146213630051300 its reverse (3150036312641), we get a palindrome (149363666363941).

The spelling of 146213630051300 in words is "one hundred forty-six trillion, two hundred thirteen billion, six hundred thirty million, fifty-one thousand, three hundred".

Divisors: 1 2 4 5 7 10 14 20 25 28 35 49 50 70 98 100 140 175 196 245 350 490 700 980 1225 2450 4900 29839516337 59679032674 119358065348 149197581685 208876614359 298395163370 417753228718 596790326740 745987908425 835506457436 1044383071795 1462136300513 1491975816850 2088766143590 2924272601026 2983951633700 4177532287180 5221915358975 5848545202052 7310681502565 10443830717950 14621363005130 20887661435900 29242726010260 36553407512825 73106815025650 146213630051300