Base | Representation |
---|---|
bin | 1000100010001101101… |
… | …1001010101000010111 |
3 | 112000110102102220122101 |
4 | 2020203123022220113 |
5 | 4400241020241210 |
6 | 151205140142531 |
7 | 13410313511305 |
oct | 2104333125027 |
9 | 460412386571 |
10 | 146623212055 |
11 | 57200a87411 |
12 | 244bb997a47 |
13 | 10a98ac2a98 |
14 | 714d107275 |
15 | 3c3240ea3a |
hex | 22236caa17 |
146623212055 has 8 divisors (see below), whose sum is σ = 180703202112. Its totient is φ = 114128337888.
The previous prime is 146623212019. The next prime is 146623212061. The reversal of 146623212055 is 550212326641.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 146623212055 - 217 = 146623080983 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 396278767 + ... + 396279136.
It is an arithmetic number, because the mean of its divisors is an integer number (22587900264).
Almost surely, 2146623212055 is an apocalyptic number.
146623212055 is a deficient number, since it is larger than the sum of its proper divisors (34079990057).
146623212055 is an equidigital number, since it uses as much as digits as its factorization.
146623212055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 792557945.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 146623212055 its reverse (550212326641), we get a palindrome (696835538696).
The spelling of 146623212055 in words is "one hundred forty-six billion, six hundred twenty-three million, two hundred twelve thousand, fifty-five".
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