Base | Representation |
---|---|
bin | 11011011001111110… |
… | …01010101100101111 |
3 | 1101222101212011112212 |
4 | 31230333022230233 |
5 | 220113112300421 |
6 | 10431555121035 |
7 | 1030416560144 |
oct | 155477125457 |
9 | 41871764485 |
10 | 14713400111 |
11 | 6270370303 |
12 | 2a275a317b |
13 | 1506360617 |
14 | 9d813c3cb |
15 | 5b1aa0e5b |
hex | 36cfcab2f |
14713400111 has 2 divisors, whose sum is σ = 14713400112. Its totient is φ = 14713400110.
The previous prime is 14713400087. The next prime is 14713400137. The reversal of 14713400111 is 11100431741.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14713400111 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14713400411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7356700055 + 7356700056.
It is an arithmetic number, because the mean of its divisors is an integer number (7356700056).
Almost surely, 214713400111 is an apocalyptic number.
14713400111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14713400111 is an equidigital number, since it uses as much as digits as its factorization.
14713400111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 14713400111 its reverse (11100431741), we get a palindrome (25813831852).
The spelling of 14713400111 in words is "fourteen billion, seven hundred thirteen million, four hundred thousand, one hundred eleven".
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