14920133 has 2 divisors, whose sum is σ = 14920134. Its totient is φ = 14920132.

The previous prime is 14920109. The next prime is 14920151. The reversal of 14920133 is 33102941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10349089 + 4571044 = 3217^2 + 2138^2 .

It is a cyclic number.

It is not a de Polignac number, because 14920133 - 2¹⁰ = 14919109 is a prime.

It is a super-2 number, since 2×14920133² = 445220737475378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14920099 and 14920108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14920933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7460066 + 7460067.

It is an arithmetic number, because the mean of its divisors is an integer number (7460067).

Almost surely, 2^14920133 is an apocalyptic number.

It is an amenable number.

14920133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14920133 is an equidigital number, since it uses as much as digits as its factorization.

14920133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 14920133 is about 3862.6587993246. The cubic root of 14920133 is about 246.1827194722.

The spelling of 14920133 in words is "fourteen million, nine hundred twenty thousand, one hundred thirty-three".