Base | Representation |
---|---|
bin | 1101100101100111111110… |
… | …1111101110011011100001 |
3 | 1221220020212001001000002022 |
4 | 3121121333233232123201 |
5 | 3424234200101112430 |
6 | 51435205343231225 |
7 | 3101245051133123 |
oct | 331317757563341 |
9 | 57806761030068 |
10 | 14940039472865 |
11 | 4840042884021 |
12 | 1813590ba8515 |
13 | 844abba03220 |
14 | 39915d379213 |
15 | 1ad95860c4e5 |
hex | d967fbee6e1 |
14940039472865 has 64 divisors (see below), whose sum is σ = 20542775565312. Its totient is φ = 10333022515200.
The previous prime is 14940039472843. The next prime is 14940039472871. The reversal of 14940039472865 is 56827493004941.
It is not a de Polignac number, because 14940039472865 - 212 = 14940039468769 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14940039472798 and 14940039472807.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 197835704 + ... + 197911206.
It is an arithmetic number, because the mean of its divisors is an integer number (320980868208).
It is a 1-persistent number, because it is pandigital, but 2⋅14940039472865 = 29880078945730 is not.
Almost surely, 214940039472865 is an apocalyptic number.
It is an amenable number.
14940039472865 is a deficient number, since it is larger than the sum of its proper divisors (5602736092447).
14940039472865 is a wasteful number, since it uses less digits than its factorization.
14940039472865 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76410.
The product of its (nonzero) digits is 52254720, while the sum is 62.
The spelling of 14940039472865 in words is "fourteen trillion, nine hundred forty billion, thirty-nine million, four hundred seventy-two thousand, eight hundred sixty-five".
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