Base | Representation |
---|---|
bin | 100010000011000010010100… |
… | …110100101100111100010000 |
3 | 201122012012212221020221221020 |
4 | 202003002110310230330100 |
5 | 124111334100040320110 |
6 | 1250250344524555440 |
7 | 43353343134351030 |
oct | 4203022464547420 |
9 | 648165787227836 |
10 | 149742236651280 |
11 | 437923648aa239 |
12 | 149650700b2b80 |
13 | 657282b2b4770 |
14 | 28d97c49438c0 |
15 | 124a214cb3d70 |
hex | 883094d2cf10 |
149742236651280 has 320 divisors, whose sum is σ = 604931534903808. Its totient is φ = 29735497728000.
The previous prime is 149742236651239. The next prime is 149742236651347. The reversal of 149742236651280 is 82156632247941.
It is a Harshad number since it is a multiple of its sum of digits (60).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 201285471 + ... + 202028030.
It is a 1-persistent number, because it is pandigital, but 2⋅149742236651280 = 299484473302560 is not.
Almost surely, 2149742236651280 is an apocalyptic number.
149742236651280 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
149742236651280 is an abundant number, since it is smaller than the sum of its proper divisors (455189298252528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
149742236651280 is a wasteful number, since it uses less digits than its factorization.
149742236651280 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 403313554 (or 403313548 counting only the distinct ones).
The product of its (nonzero) digits is 34836480, while the sum is 60.
The spelling of 149742236651280 in words is "one hundred forty-nine trillion, seven hundred forty-two billion, two hundred thirty-six million, six hundred fifty-one thousand, two hundred eighty".
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