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150343540111 = 2313747712961
BaseRepresentation
bin1000110000000100101…
…1000101110110001111
3112101001200220011022101
42030001023011312033
54430400421240421
6153022235455531
713601440001632
oct2140113056617
9471050804271
10150343540111
11588400109a6
12251798b75a7
131123c7b322b
1473c3259c19
153d9dd3e191
hex23012c5d8f

150343540111 has 8 divisors (see below), whose sum is σ = 158025330144. Its totient is φ = 142757176320.

The previous prime is 150343540103. The next prime is 150343540147. The reversal of 150343540111 is 111045343051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 150343540111 - 23 = 150343540103 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 150343540111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150343540411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23853330 + ... + 23859631.

It is an arithmetic number, because the mean of its divisors is an integer number (19753166268).

Almost surely, 2150343540111 is an apocalyptic number.

150343540111 is a deficient number, since it is larger than the sum of its proper divisors (7681790033).

150343540111 is a wasteful number, since it uses less digits than its factorization.

150343540111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47713121.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 150343540111 its reverse (111045343051), we get a palindrome (261388883162).

The spelling of 150343540111 in words is "one hundred fifty billion, three hundred forty-three million, five hundred forty thousand, one hundred eleven".

Divisors: 1 23 137 3151 47712961 1097398103 6536675657 150343540111