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15100506000551 is a prime number
BaseRepresentation
bin1101101110111101110001…
…0010111100110010100111
31222110121001020010012202102
43123233130102330302213
53434401314014004201
652041024322002315
73115655421123266
oct333573422746247
958417036105672
1015100506000551
1148a20a7a71354
12183a6b4aa639b
13856c8280561a
143a2c22c105dd
151b2beb00026b
hexdbbdc4bcca7

15100506000551 has 2 divisors, whose sum is σ = 15100506000552. Its totient is φ = 15100506000550.

The previous prime is 15100506000529. The next prime is 15100506000553. The reversal of 15100506000551 is 15500060500151.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15100506000551 - 214 = 15100505984167 is a prime.

It is a super-2 number, since 2×151005060005512 (a number of 27 digits) contains 22 as substring.

Together with 15100506000553, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15100506000553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7550253000275 + 7550253000276.

It is an arithmetic number, because the mean of its divisors is an integer number (7550253000276).

Almost surely, 215100506000551 is an apocalyptic number.

15100506000551 is a deficient number, since it is larger than the sum of its proper divisors (1).

15100506000551 is an equidigital number, since it uses as much as digits as its factorization.

15100506000551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3750, while the sum is 29.

The spelling of 15100506000551 in words is "fifteen trillion, one hundred billion, five hundred six million, five hundred fifty-one", and thus it is an aban number.