Base | Representation |
---|---|
bin | 1000110010101000011… |
… | …0010001010100011011 |
3 | 112102211112212011100200 |
4 | 2030222012101110123 |
5 | 4433302204022420 |
6 | 153214324033243 |
7 | 13624445012250 |
oct | 2145206212433 |
9 | 472745764320 |
10 | 151030142235 |
11 | 5906263a275 |
12 | 2532b832823 |
13 | 1131bb1128b |
14 | 744a507427 |
15 | 3dde266b90 |
hex | 232a19151b |
151030142235 has 24 divisors (see below), whose sum is σ = 299183520480. Its totient is φ = 69042350592.
The previous prime is 151030142177. The next prime is 151030142273. The reversal of 151030142235 is 532241030151.
151030142235 is a `hidden beast` number, since 1 + 510 + 3 + 0 + 142 + 2 + 3 + 5 = 666.
It is not a de Polignac number, because 151030142235 - 222 = 151025947931 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 151030142199 and 151030142208.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 239730070 + ... + 239730699.
It is an arithmetic number, because the mean of its divisors is an integer number (12465980020).
Almost surely, 2151030142235 is an apocalyptic number.
151030142235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
151030142235 is a deficient number, since it is larger than the sum of its proper divisors (148153378245).
151030142235 is a wasteful number, since it uses less digits than its factorization.
151030142235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 479460787 (or 479460784 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 151030142235 its reverse (532241030151), we get a palindrome (683271172386).
The spelling of 151030142235 in words is "one hundred fifty-one billion, thirty million, one hundred forty-two thousand, two hundred thirty-five".
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