151111440131 has 4 divisors (see below), whose sum is σ = 160000348392. Its totient is φ = 142222531872.

The previous prime is 151111440119. The next prime is 151111440133. The reversal of 151111440131 is 131044111151.

151111440131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 151111440131 - 2²⁶ = 151044331267 is a prime.

It is a super-2 number, since 2×151111440131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 151111440097 and 151111440106.

It is not an unprimeable number, because it can be changed into a prime (151111440133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4444454105 + ... + 4444454138.

It is an arithmetic number, because the mean of its divisors is an integer number (40000087098).

Almost surely, 2^151111440131 is an apocalyptic number.

151111440131 is a deficient number, since it is larger than the sum of its proper divisors (8888908261).

151111440131 is an equidigital number, since it uses as much as digits as its factorization.

151111440131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8888908260.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 151111440131 its reverse (131044111151), we get a palindrome (282155551282).

The spelling of 151111440131 in words is "one hundred fifty-one billion, one hundred eleven million, four hundred forty thousand, one hundred thirty-one".