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15125043133 = 23657610571
BaseRepresentation
bin11100001011000010…
…11101011110111101
31110001002102210121201
432011201131132331
5221434002340013
610540502055501
71043545513444
oct160541353675
943032383551
1015125043133
116461768852
122b2141a591
13157071a585
14a36a93d5b
155d7cb43dd
hex38585d7bd

15125043133 has 4 divisors (see below), whose sum is σ = 15782653728. Its totient is φ = 14467432540.

The previous prime is 15125043091. The next prime is 15125043149. The reversal of 15125043133 is 33134052151.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15125043133 is a prime.

It is a super-2 number, since 2×151250431332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15125043533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328805263 + ... + 328805308.

It is an arithmetic number, because the mean of its divisors is an integer number (3945663432).

Almost surely, 215125043133 is an apocalyptic number.

It is an amenable number.

15125043133 is a deficient number, since it is larger than the sum of its proper divisors (657610595).

15125043133 is an equidigital number, since it uses as much as digits as its factorization.

15125043133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 657610594.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 15125043133 its reverse (33134052151), we get a palindrome (48259095284).

The spelling of 15125043133 in words is "fifteen billion, one hundred twenty-five million, forty-three thousand, one hundred thirty-three".

Divisors: 1 23 657610571 15125043133