Base | Representation |
---|---|
bin | 10110000001101001110… |
… | …101111011001101110101 |
3 | 12100200212200101201201222 |
4 | 112001221311323031311 |
5 | 144244330140411203 |
6 | 3115201251400125 |
7 | 214232344456454 |
oct | 26015165731565 |
9 | 5320780351658 |
10 | 1513604232053 |
11 | 533a09147281 |
12 | 20541abb3045 |
13 | ac969a36264 |
14 | 5338a360b9b |
15 | 2958b8a3038 |
hex | 16069d7b375 |
1513604232053 has 4 divisors (see below), whose sum is σ = 1513607059008. Its totient is φ = 1513601405100.
The previous prime is 1513604232029. The next prime is 1513604232067. The reversal of 1513604232053 is 3502324063151.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1513604232053 - 222 = 1513600037749 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1513604232083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337151 + ... + 1772252.
It is an arithmetic number, because the mean of its divisors is an integer number (378401764752).
Almost surely, 21513604232053 is an apocalyptic number.
It is an amenable number.
1513604232053 is a deficient number, since it is larger than the sum of its proper divisors (2826955).
1513604232053 is an equidigital number, since it uses as much as digits as its factorization.
1513604232053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2826954.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 1513604232053 in words is "one trillion, five hundred thirteen billion, six hundred four million, two hundred thirty-two thousand, fifty-three".
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