152024333 has 2 divisors, whose sum is σ = 152024334. Its totient is φ = 152024332.

The previous prime is 152024329. The next prime is 152024381. The reversal of 152024333 is 333420251.

152024333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 151708489 + 315844 = 12317^2 + 562^2 .

It is an emirp because it is prime and its reverse (333420251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 152024333 - 2² = 152024329 is a prime.

It is a super-2 number, since 2×152024333² = 46222795648189778, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 152024299 and 152024308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152024303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76012166 + 76012167.

It is an arithmetic number, because the mean of its divisors is an integer number (76012167).

Almost surely, 2^152024333 is an apocalyptic number.

It is an amenable number.

152024333 is a deficient number, since it is larger than the sum of its proper divisors (1).

152024333 is an equidigital number, since it uses as much as digits as its factorization.

152024333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 152024333 is about 12329.8147999068. The cubic root of 152024333 is about 533.7088063904.

Adding to 152024333 its reverse (333420251), we get a palindrome (485444584).

The spelling of 152024333 in words is "one hundred fifty-two million, twenty-four thousand, three hundred thirty-three".