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1523114311093 is a prime number
BaseRepresentation
bin10110001010100000101…
…011111111110110110101
312101121102110021210122121
4112022200223333312311
5144423314230423333
63123413053355541
7215020123013434
oct26124053776665
95347373253577
101523114311093
11537a49359431
12207233a98bb1
13b082408a16b
1453a0d3d311b
152994673932d
hex162a0affdb5

1523114311093 has 2 divisors, whose sum is σ = 1523114311094. Its totient is φ = 1523114311092.

The previous prime is 1523114311091. The next prime is 1523114311127. The reversal of 1523114311093 is 3901134113251.

It is an a-pointer prime, because the next prime (1523114311127) can be obtained adding 1523114311093 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1510839222244 + 12275088849 = 1229162^2 + 110793^2 .

It is an emirp because it is prime and its reverse (3901134113251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1523114311093 - 21 = 1523114311091 is a prime.

Together with 1523114311091, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1523114311091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 761557155546 + 761557155547.

It is an arithmetic number, because the mean of its divisors is an integer number (761557155547).

Almost surely, 21523114311093 is an apocalyptic number.

It is an amenable number.

1523114311093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1523114311093 is an equidigital number, since it uses as much as digits as its factorization.

1523114311093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 34.

The spelling of 1523114311093 in words is "one trillion, five hundred twenty-three billion, one hundred fourteen million, three hundred eleven thousand, ninety-three".