| Base | Representation |
|---|---|
| bin | 11100011010010100… |
| … | …00111101001110010 |
| 3 | 1110101000110220102000 |
| 4 | 32031022013221302 |
| 5 | 222214301022010 |
| 6 | 11001315434430 |
| 7 | 1046662366062 |
| oct | 161512075162 |
| 9 | 43330426360 |
| 10 | 15253142130 |
| 11 | 6518001496 |
| 12 | 2b582b5a16 |
| 13 | 159111b9b5 |
| 14 | a49abb3a2 |
| 15 | 5e41697c0 |
| hex | 38d287a72 |
15253142130 has 64 divisors (see below), whose sum is σ = 40689993600. Its totient is φ = 4066009920.
The previous prime is 15253142129. The next prime is 15253142131. The reversal of 15253142130 is 3124135251.
15253142130 is a `hidden beast` number, since 1 + 525 + 3 + 1 + 4 + 2 + 130 = 666.
15253142130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (15253142129) and next prime (15253142131).
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 15253142094 and 15253142103.
It is not an unprimeable number, because it can be changed into a prime (15253142131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 860901 + ... + 878439.
It is an arithmetic number, because the mean of its divisors is an integer number (635781150).
Almost surely, 215253142130 is an apocalyptic number.
15253142130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
15253142130 is an abundant number, since it is smaller than the sum of its proper divisors (25436851470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15253142130 is a wasteful number, since it uses less digits than its factorization.
15253142130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20776 (or 20770 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 15253142130 its reverse (3124135251), we get a palindrome (18377277381).
The spelling of 15253142130 in words is "fifteen billion, two hundred fifty-three million, one hundred forty-two thousand, one hundred thirty".
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