Search a number
-
+
15303013143 = 3112411028221
BaseRepresentation
bin11100100000010000…
…10111001100010111
31110111111022121120120
432100020113030113
5222320032410033
611010300403023
71051136315445
oct162010271427
943444277516
1015303013143
116543174300
122b70b46473
13159b560482
14a5257db95
155e871b1b3
hex390217317

15303013143 has 24 divisors (see below), whose sum is σ = 22974592368. Its totient is φ = 9048336000.

The previous prime is 15303013123. The next prime is 15303013153. The reversal of 15303013143 is 34131030351.

It is not a de Polignac number, because 15303013143 - 212 = 15303009047 is a prime.

It is a super-2 number, since 2×153030131432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15303013123) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 499228 + ... + 528993.

It is an arithmetic number, because the mean of its divisors is an integer number (957274682).

Almost surely, 215303013143 is an apocalyptic number.

15303013143 is a deficient number, since it is larger than the sum of its proper divisors (7671579225).

15303013143 is a wasteful number, since it uses less digits than its factorization.

15303013143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1028287 (or 1028276 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 24.

Adding to 15303013143 its reverse (34131030351), we get a palindrome (49434043494).

The spelling of 15303013143 in words is "fifteen billion, three hundred three million, thirteen thousand, one hundred forty-three".

Divisors: 1 3 11 33 41 121 123 363 451 1353 4961 14883 1028221 3084663 11310431 33931293 42157061 124414741 126471183 373244223 463727671 1391183013 5101004381 15303013143