Base | Representation |
---|---|
bin | 100010110110000101100101… |
… | …011100010010100001100100 |
3 | 202002121121010221222100122002 |
4 | 202312011211130102201210 |
5 | 130041323340040101200 |
6 | 1301534135311424432 |
7 | 44164656343003250 |
oct | 4266054534224144 |
9 | 662547127870562 |
10 | 153250430003300 |
11 | 44915162563013 |
12 | 15230b62b25118 |
13 | 67685b8572906 |
14 | 29bb508c99260 |
15 | 12ab5de5cabd5 |
hex | 8b6165712864 |
153250430003300 has 72 divisors (see below), whose sum is σ = 380063957683200. Its totient is φ = 52542604857600.
The previous prime is 153250430003287. The next prime is 153250430003327. The reversal of 153250430003300 is 3300034052351.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 99955901 + ... + 101477499.
Almost surely, 2153250430003300 is an apocalyptic number.
153250430003300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
153250430003300 is an abundant number, since it is smaller than the sum of its proper divisors (226813527679900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
153250430003300 is a wasteful number, since it uses less digits than its factorization.
153250430003300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1665501 (or 1665494 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 29.
Adding to 153250430003300 its reverse (3300034052351), we get a palindrome (156550464055651).
The spelling of 153250430003300 in words is "one hundred fifty-three trillion, two hundred fifty billion, four hundred thirty million, three thousand, three hundred".
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