15404162133 has 4 divisors (see below), whose sum is σ = 20538882848. Its totient is φ = 10269441420.

The previous prime is 15404162131. The next prime is 15404162171. The reversal of 15404162133 is 33126140451.

15404162133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33126140451 = 3 ⋅11042046817.

It is not a de Polignac number, because 15404162133 - 2¹ = 15404162131 is a prime.

It is a super-2 number, since 2×15404162133² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 15404162133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15404162131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2567360353 + ... + 2567360358.

It is an arithmetic number, because the mean of its divisors is an integer number (5134720712).

Almost surely, 2^15404162133 is an apocalyptic number.

It is an amenable number.

15404162133 is a deficient number, since it is larger than the sum of its proper divisors (5134720715).

15404162133 is an equidigital number, since it uses as much as digits as its factorization.

15404162133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5134720714.

The product of its (nonzero) digits is 8640, while the sum is 30.

The spelling of 15404162133 in words is "fifteen billion, four hundred four million, one hundred sixty-two thousand, one hundred thirty-three".