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154112021430013 is a prime number
BaseRepresentation
bin100011000010101000000000…
…010010101111111011111101
3202012122222001202020202102001
4203002220000102233323331
5130144432404441230023
61303434030230102301
744314140362205103
oct4302500022577375
9665588052222361
10154112021430013
11451175a5450259
121534bb381aa991
1367cb91689cb7a
142a0b0c11b5c73
1512c3c19bc96ad
hex8c2a004afefd

154112021430013 has 2 divisors, whose sum is σ = 154112021430014. Its totient is φ = 154112021430012.

The previous prime is 154112021429963. The next prime is 154112021430041. The reversal of 154112021430013 is 310034120211451.

It is an a-pointer prime, because the next prime (154112021430041) can be obtained adding 154112021430013 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104911715140164 + 49200306289849 = 10242642^2 + 7014293^2 .

It is an emirp because it is prime and its reverse (310034120211451) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 154112021430013 - 217 = 154112021298941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154112021437013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77056010715006 + 77056010715007.

It is an arithmetic number, because the mean of its divisors is an integer number (77056010715007).

Almost surely, 2154112021430013 is an apocalyptic number.

It is an amenable number.

154112021430013 is a deficient number, since it is larger than the sum of its proper divisors (1).

154112021430013 is an equidigital number, since it uses as much as digits as its factorization.

154112021430013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 154112021430013 its reverse (310034120211451), we get a palindrome (464146141641464).

The spelling of 154112021430013 in words is "one hundred fifty-four trillion, one hundred twelve billion, twenty-one million, four hundred thirty thousand, thirteen".