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154154713249 is a prime number
BaseRepresentation
bin1000111110010001010…
…1100100000010100001
3112201220022021211000001
42033210111210002201
510011202101310444
6154452342300001
714065045304605
oct2174425440241
9481808254001
10154154713249
115a416353769
1225a62127601
13116c9260174
147665499505
1540237158d4
hex23e45640a1

154154713249 has 2 divisors, whose sum is σ = 154154713250. Its totient is φ = 154154713248.

The previous prime is 154154713247. The next prime is 154154713313. The reversal of 154154713249 is 942317451451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154154390625 + 322624 = 392625^2 + 568^2 .

It is a cyclic number.

It is not a de Polignac number, because 154154713249 - 21 = 154154713247 is a prime.

It is a super-2 number, since 2×1541547132492 (a number of 23 digits) contains 22 as substring.

Together with 154154713247, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 154154713199 and 154154713208.

It is not a weakly prime, because it can be changed into another prime (154154713241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77077356624 + 77077356625.

It is an arithmetic number, because the mean of its divisors is an integer number (77077356625).

Almost surely, 2154154713249 is an apocalyptic number.

It is an amenable number.

154154713249 is a deficient number, since it is larger than the sum of its proper divisors (1).

154154713249 is an equidigital number, since it uses as much as digits as its factorization.

154154713249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 604800, while the sum is 46.

The spelling of 154154713249 in words is "one hundred fifty-four billion, one hundred fifty-four million, seven hundred thirteen thousand, two hundred forty-nine".