Base | Representation |
---|---|
bin | 1110110001011111011010… |
… | …1101011001100010101101 |
3 | 2010111212002012110110012110 |
4 | 3230113312231121202231 |
5 | 4112113001033124123 |
6 | 54314041510354233 |
7 | 3264355565442210 |
oct | 354276655314255 |
9 | 63455065413173 |
10 | 16243410442413 |
11 | 51a2878803560 |
12 | 19a40b935b979 |
13 | 90a9932ca8ab |
14 | 4022844d5777 |
15 | 1d27dd453493 |
hex | ec5f6b598ad |
16243410442413 has 64 divisors (see below), whose sum is σ = 27240485437440. Its totient is φ = 8363881843200.
The previous prime is 16243410442411. The next prime is 16243410442433. The reversal of 16243410442413 is 31424401434261.
It is not a de Polignac number, because 16243410442413 - 21 = 16243410442411 is a prime.
It is a super-3 number, since 3×162434104424133 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16243410442411) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14285668 + ... + 15380738.
It is an arithmetic number, because the mean of its divisors is an integer number (425632584960).
Almost surely, 216243410442413 is an apocalyptic number.
It is an amenable number.
16243410442413 is a deficient number, since it is larger than the sum of its proper divisors (10997074995027).
16243410442413 is a wasteful number, since it uses less digits than its factorization.
16243410442413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1095658.
The product of its (nonzero) digits is 221184, while the sum is 39.
Adding to 16243410442413 its reverse (31424401434261), we get a palindrome (47667811876674).
The spelling of 16243410442413 in words is "sixteen trillion, two hundred forty-three billion, four hundred ten million, four hundred forty-two thousand, four hundred thirteen".
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