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1630452228907 is a prime number
BaseRepresentation
bin10111101110011110100…
…001101010001100101011
312202212111000111222210011
4113232132201222030223
5203203131232311112
63245004105432351
7225540061164355
oct27563641521453
95685430458704
101630452228907
1157951a860817
12223bab19b6b7
13ba99bbb84b8
1458cb2c140d5
152c629c8baa7
hex17b9e86a32b

1630452228907 has 2 divisors, whose sum is σ = 1630452228908. Its totient is φ = 1630452228906.

The previous prime is 1630452228901. The next prime is 1630452228913. The reversal of 1630452228907 is 7098222540361.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1630452228901) and next prime (1630452228913).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1630452228907 is a prime.

It is not a weakly prime, because it can be changed into another prime (1630452228901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 815226114453 + 815226114454.

It is an arithmetic number, because the mean of its divisors is an integer number (815226114454).

It is a 2-persistent number, because it is pandigital, and so is 2⋅1630452228907 = 3260904457814, but 3⋅1630452228907 = 4891356686721 is not.

Almost surely, 21630452228907 is an apocalyptic number.

1630452228907 is a deficient number, since it is larger than the sum of its proper divisors (1).

1630452228907 is an equidigital number, since it uses as much as digits as its factorization.

1630452228907 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 49.

The spelling of 1630452228907 in words is "one trillion, six hundred thirty billion, four hundred fifty-two million, two hundred twenty-eight thousand, nine hundred seven".