Base | Representation |
---|---|
bin | 100101000110000011101111… |
… | …010011011110111110100011 |
3 | 210101122102022112102022111112 |
4 | 211012003233103132332203 |
5 | 132340423004433233012 |
6 | 1334551202040333535 |
7 | 46235524465544321 |
oct | 4506035723367643 |
9 | 711572275368445 |
10 | 163144052633507 |
11 | 47a8a005611690 |
12 | 1636a4b11742ab |
13 | 70055588a59ba |
14 | 2c402ddda4d11 |
15 | 13cdb404a8122 |
hex | 9460ef4defa3 |
163144052633507 has 4 divisors (see below), whose sum is σ = 177975330145656. Its totient is φ = 148312775121360.
The previous prime is 163144052633489. The next prime is 163144052633539. The reversal of 163144052633507 is 705336250441361.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-163144052633507 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (163144052633557) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7415638756058 + ... + 7415638756079.
It is an arithmetic number, because the mean of its divisors is an integer number (44493832536414).
Almost surely, 2163144052633507 is an apocalyptic number.
163144052633507 is a deficient number, since it is larger than the sum of its proper divisors (14831277512149).
163144052633507 is a wasteful number, since it uses less digits than its factorization.
163144052633507 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14831277512148.
The product of its (nonzero) digits is 5443200, while the sum is 50.
The spelling of 163144052633507 in words is "one hundred sixty-three trillion, one hundred forty-four billion, fifty-two million, six hundred thirty-three thousand, five hundred seven".
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