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16340117 is a prime number
BaseRepresentation
bin111110010101…
…010010010101
31010202011102112
4332111102111
513140340432
61342120405
7255613553
oct76252225
933664375
1016340117
119250632
125580105
133501611
142254bd3
15167b7b2
hexf95495

16340117 has 2 divisors, whose sum is σ = 16340118. Its totient is φ = 16340116.

The previous prime is 16340113. The next prime is 16340147. The reversal of 16340117 is 71104361.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9296401 + 7043716 = 3049^2 + 2654^2 .

It is a cyclic number.

It is not a de Polignac number, because 16340117 - 22 = 16340113 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 16340092 and 16340101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16340113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8170058 + 8170059.

It is an arithmetic number, because the mean of its divisors is an integer number (8170059).

Almost surely, 216340117 is an apocalyptic number.

It is an amenable number.

16340117 is a deficient number, since it is larger than the sum of its proper divisors (1).

16340117 is an equidigital number, since it uses as much as digits as its factorization.

16340117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 16340117 is about 4042.2910582985. The cubic root of 16340117 is about 253.7572080103.

Adding to 16340117 its reverse (71104361), we get a palindrome (87444478).

The spelling of 16340117 in words is "sixteen million, three hundred forty thousand, one hundred seventeen".