1640000113 has 4 divisors (see below), whose sum is σ = 1640096368. Its totient is φ = 1639903860.

The previous prime is 1640000111. The next prime is 1640000129. The reversal of 1640000113 is 3110000461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3110000461 = 37579 ⋅82759.

It is a cyclic number.

It is not a de Polignac number, because 1640000113 - 2¹ = 1640000111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1640000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14943 + ... + 59188.

It is an arithmetic number, because the mean of its divisors is an integer number (410024092).

Almost surely, 2^1640000113 is an apocalyptic number.

It is an amenable number.

1640000113 is a deficient number, since it is larger than the sum of its proper divisors (96255).

1640000113 is an equidigital number, since it uses as much as digits as its factorization.

1640000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96254.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1640000113 is about 40496.9148578012. The cubic root of 1640000113 is about 1179.2737350790.

Adding to 1640000113 its reverse (3110000461), we get a palindrome (4750000574).

The spelling of 1640000113 in words is "one billion, six hundred forty million, one hundred thirteen", and thus it is an aban number.