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1644414103 is a prime number
BaseRepresentation
bin110001000000011…
…1100010010010111
311020121020220002001
41202000330102113
511331432222403
6431101300131
755515201133
oct14200742227
94217226061
101644414103
11774257722
1239a864647
132028b67c7
141185763c3
1599573c1d
hex6203c497

1644414103 has 2 divisors, whose sum is σ = 1644414104. Its totient is φ = 1644414102.

The previous prime is 1644414089. The next prime is 1644414113. The reversal of 1644414103 is 3014144461.

It is a strong prime.

It is an emirp because it is prime and its reverse (3014144461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1644414103 - 29 = 1644413591 is a prime.

It is a super-3 number, since 3×16444141033 (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1644414113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 822207051 + 822207052.

It is an arithmetic number, because the mean of its divisors is an integer number (822207052).

Almost surely, 21644414103 is an apocalyptic number.

1644414103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1644414103 is an equidigital number, since it uses as much as digits as its factorization.

1644414103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

The square root of 1644414103 is about 40551.3760925570. The cubic root of 1644414103 is about 1180.3307755539.

Adding to 1644414103 its reverse (3014144461), we get a palindrome (4658558564).

The spelling of 1644414103 in words is "one billion, six hundred forty-four million, four hundred fourteen thousand, one hundred three".