Base | Representation |
---|---|
bin | 1110111110001010001111… |
… | …0001101110110100010100 |
3 | 2011021122212202000120001221 |
4 | 3233202203301232310110 |
5 | 4124144223433320200 |
6 | 55002035131300124 |
7 | 3316162320533206 |
oct | 357424361566424 |
9 | 64248782016057 |
10 | 16461062401300 |
11 | 527710864a730 |
12 | 1a1a3205aa644 |
13 | 92536b6cb94a |
14 | 40ca10ac6776 |
15 | 1d82cb43291a |
hex | ef8a3c6ed14 |
16461062401300 has 36 divisors (see below), whose sum is σ = 38967824087136. Its totient is φ = 5985840872800.
The previous prime is 16461062401271. The next prime is 16461062401307. The reversal of 16461062401300 is 310426016461.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16461062401307) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7482299992 + ... + 7482302191.
It is an arithmetic number, because the mean of its divisors is an integer number (1082439557976).
Almost surely, 216461062401300 is an apocalyptic number.
16461062401300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
16461062401300 is an abundant number, since it is smaller than the sum of its proper divisors (22506761685836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
16461062401300 is a wasteful number, since it uses less digits than its factorization.
16461062401300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14964602208 (or 14964602201 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 34.
Adding to 16461062401300 its reverse (310426016461), we get a palindrome (16771488417761).
The spelling of 16461062401300 in words is "sixteen trillion, four hundred sixty-one billion, sixty-two million, four hundred one thousand, three hundred".
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