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16495845407 is a prime number
BaseRepresentation
bin11110101110011101…
…01010000000011111
31120120121211202211022
433113032222000133
5232240414023112
611324511114355
71122532241516
oct172716520037
946517752738
1016495845407
116aa5524898
1232445129bb
13172b715292
14b26b6567d
156682dcd72
hex3d73aa01f

16495845407 has 2 divisors, whose sum is σ = 16495845408. Its totient is φ = 16495845406.

The previous prime is 16495845397. The next prime is 16495845409. The reversal of 16495845407 is 70454859461.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16495845407 - 212 = 16495841311 is a prime.

It is a super-2 number, since 2×164958454072 (a number of 21 digits) contains 22 as substring.

Together with 16495845409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16495845409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8247922703 + 8247922704.

It is an arithmetic number, because the mean of its divisors is an integer number (8247922704).

Almost surely, 216495845407 is an apocalyptic number.

16495845407 is a deficient number, since it is larger than the sum of its proper divisors (1).

16495845407 is an equidigital number, since it uses as much as digits as its factorization.

16495845407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 16495845407 in words is "sixteen billion, four hundred ninety-five million, eight hundred forty-five thousand, four hundred seven".