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168140503901 is a prime number
BaseRepresentation
bin1001110010010111110…
…1000111101101011101
3121002000000000121000102
42130211331013231131
510223322432111101
6205124230310445
715101451462506
oct2344575075535
9532000017012
10168140503901
1165342a27237
1228705ab8425
1312b17935536
1481d0b13bad
15459148d86b
hex2725f47b5d

168140503901 has 2 divisors, whose sum is σ = 168140503902. Its totient is φ = 168140503900.

The previous prime is 168140503889. The next prime is 168140503903. The reversal of 168140503901 is 109305041861.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 145565140900 + 22575363001 = 381530^2 + 150251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-168140503901 is a prime.

Together with 168140503903, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (168140503903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84070251950 + 84070251951.

It is an arithmetic number, because the mean of its divisors is an integer number (84070251951).

Almost surely, 2168140503901 is an apocalyptic number.

It is an amenable number.

168140503901 is a deficient number, since it is larger than the sum of its proper divisors (1).

168140503901 is an equidigital number, since it uses as much as digits as its factorization.

168140503901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 38.

The spelling of 168140503901 in words is "one hundred sixty-eight billion, one hundred forty million, five hundred three thousand, nine hundred one".