Base | Representation |
---|---|
bin | 11111111000001001… |
… | …10101111110111011 |
3 | 1122011201001210200101 |
4 | 33330010311332323 |
5 | 240022142430021 |
6 | 11510113020231 |
7 | 1144046566141 |
oct | 177404657673 |
9 | 48151053611 |
10 | 17114030011 |
11 | 7292473061 |
12 | 3397554677 |
13 | 17c9809ba0 |
14 | b84cc3591 |
15 | 6a26eda91 |
hex | 3fc135fbb |
17114030011 has 4 divisors (see below), whose sum is σ = 18430493872. Its totient is φ = 15797566152.
The previous prime is 17114029969. The next prime is 17114030023. The reversal of 17114030011 is 11003041171.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11003041171 = 3323 ⋅3311177.
It is a cyclic number.
It is not a de Polignac number, because 17114030011 - 211 = 17114027963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (17114030051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 658231911 + ... + 658231936.
It is an arithmetic number, because the mean of its divisors is an integer number (4607623468).
Almost surely, 217114030011 is an apocalyptic number.
17114030011 is a deficient number, since it is larger than the sum of its proper divisors (1316463861).
17114030011 is a wasteful number, since it uses less digits than its factorization.
17114030011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1316463860.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 17114030011 its reverse (11003041171), we get a palindrome (28117071182).
The spelling of 17114030011 in words is "seventeen billion, one hundred fourteen million, thirty thousand, eleven".
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