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17132117 is a prime number
BaseRepresentation
bin100000101011…
…0101001010101
31012020101211212
41001112221111
513341211432
61411111205
7265422602
oct101265125
935211755
1017132117
119741682
1258a2505
13371ac62
1423bd6a9
1517862b2
hex1056a55

17132117 has 2 divisors, whose sum is σ = 17132118. Its totient is φ = 17132116.

The previous prime is 17132077. The next prime is 17132123. The reversal of 17132117 is 71123171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17023876 + 108241 = 4126^2 + 329^2 .

It is a cyclic number.

It is not a de Polignac number, because 17132117 - 214 = 17115733 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 17132092 and 17132101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17132317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8566058 + 8566059.

It is an arithmetic number, because the mean of its divisors is an integer number (8566059).

Almost surely, 217132117 is an apocalyptic number.

It is an amenable number.

17132117 is a deficient number, since it is larger than the sum of its proper divisors (1).

17132117 is an equidigital number, since it uses as much as digits as its factorization.

17132117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 294, while the sum is 23.

The square root of 17132117 is about 4139.0961573754. The cubic root of 17132117 is about 257.7925389896.

Adding to 17132117 its reverse (71123171), we get a palindrome (88255288).

The spelling of 17132117 in words is "seventeen million, one hundred thirty-two thousand, one hundred seventeen".