Base | Representation |
---|---|
bin | 11111111011010110… |
… | …00101011010111101 |
3 | 1122020120111111000011 |
4 | 33331223011122331 |
5 | 240101023110213 |
6 | 11512511303221 |
7 | 1144523444641 |
oct | 177553053275 |
9 | 48216444004 |
10 | 17140831933 |
11 | 72a6609805 |
12 | 33a451ab11 |
13 | 1802232304 |
14 | b8869cc21 |
15 | 6a4c4503d |
hex | 3fdac56bd |
17140831933 has 2 divisors, whose sum is σ = 17140831934. Its totient is φ = 17140831932.
The previous prime is 17140831847. The next prime is 17140831943. The reversal of 17140831933 is 33913804171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17140831929 + 4 = 130923^2 + 2^2 .
It is a cyclic number.
It is not a de Polignac number, because 17140831933 - 225 = 17107277501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17140831943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8570415966 + 8570415967.
It is an arithmetic number, because the mean of its divisors is an integer number (8570415967).
Almost surely, 217140831933 is an apocalyptic number.
It is an amenable number.
17140831933 is a deficient number, since it is larger than the sum of its proper divisors (1).
17140831933 is an equidigital number, since it uses as much as digits as its factorization.
17140831933 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 17140831933 in words is "seventeen billion, one hundred forty million, eight hundred thirty-one thousand, nine hundred thirty-three".
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