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171934000541 is a prime number
BaseRepresentation
bin1010000000100000010…
…0001010010110011101
3121102210101011012002222
42200020010022112131
510304110101004131
6210552502155125
715264453614462
oct2401004122635
9542711135088
10171934000541
1166a0a296426
12293a4422aa5
13132a08337c4
148470871669
15471452287b
hex280810a59d

171934000541 has 2 divisors, whose sum is σ = 171934000542. Its totient is φ = 171934000540.

The previous prime is 171934000507. The next prime is 171934000543. The reversal of 171934000541 is 145000439171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 158790295225 + 13143705316 = 398485^2 + 114646^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-171934000541 is a prime.

It is a super-2 number, since 2×1719340005412 (a number of 23 digits) contains 22 as substring.

Together with 171934000543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171934000543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85967000270 + 85967000271.

It is an arithmetic number, because the mean of its divisors is an integer number (85967000271).

Almost surely, 2171934000541 is an apocalyptic number.

It is an amenable number.

171934000541 is a deficient number, since it is larger than the sum of its proper divisors (1).

171934000541 is an equidigital number, since it uses as much as digits as its factorization.

171934000541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 35.

The spelling of 171934000541 in words is "one hundred seventy-one billion, nine hundred thirty-four million, five hundred forty-one", and thus it is an aban number.