Search a number
-
+
18770053 is a prime number
BaseRepresentation
bin100011110011…
…0100010000101
31022022121200011
41013212202011
514301120203
61510150221
7315354121
oct107464205
938277604
1018770053
11a660245
126352371
133b72653
1426c8581
1519ab76d
hex11e6885

18770053 has 2 divisors, whose sum is σ = 18770054. Its totient is φ = 18770052.

The previous prime is 18770051. The next prime is 18770071. The reversal of 18770053 is 35007781.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17288964 + 1481089 = 4158^2 + 1217^2 .

It is an emirp because it is prime and its reverse (35007781) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 18770053 - 21 = 18770051 is a prime.

Together with 18770051, it forms a pair of twin primes.

It is equal to p1197337 and since 18770053 and 1197337 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 18769997 and 18770024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (18770051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9385026 + 9385027.

It is an arithmetic number, because the mean of its divisors is an integer number (9385027).

Almost surely, 218770053 is an apocalyptic number.

It is an amenable number.

18770053 is a deficient number, since it is larger than the sum of its proper divisors (1).

18770053 is an equidigital number, since it uses as much as digits as its factorization.

18770053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5880, while the sum is 31.

The square root of 18770053 is about 4332.4419211341. The cubic root of 18770053 is about 265.7593174068.

The spelling of 18770053 in words is "eighteen million, seven hundred seventy thousand, fifty-three".