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189904000000 = 21056111383
BaseRepresentation
bin1011000011011100101…
…0010001010000000000
3200011011201212202010111
42300313022101100000
511102410411000000
6223123553441104
716501666236451
oct2606712212000
9604151782114
10189904000000
11735a0947a50
123097a570194
1314ba578ba90
1492972cd128
154e16e51cba
hex2c37291400

189904000000 has 616 divisors, whose sum is σ = 564197153184. Its totient is φ = 62976000000.

The previous prime is 189903999991. The next prime is 189904000003. The reversal of 189904000000 is 409981.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (189904000003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2287999959 + ... + 2288000041.

Almost surely, 2189904000000 is an apocalyptic number.

189904000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 189904000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (282098576592).

189904000000 is an abundant number, since it is smaller than the sum of its proper divisors (374293153184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

189904000000 is an frugal number, since it uses more digits than its factorization.

189904000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157 (or 114 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 31.

Adding to 189904000000 its reverse (409981), we get a palindrome (189904409981).

The spelling of 189904000000 in words is "one hundred eighty-nine billion, nine hundred four million", and thus it is an aban number.