19850053 has 4 divisors (see below), whose sum is σ = 19881568. Its totient is φ = 19818540.

The previous prime is 19850021. The next prime is 19850059. The reversal of 19850053 is 35005891.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35005891 = 199 ⋅175909.

It is a cyclic number.

It is not a de Polignac number, because 19850053 - 2⁵ = 19850021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 19849997 and 19850024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19850059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14793 + ... + 16078.

It is an arithmetic number, because the mean of its divisors is an integer number (4970392).

Almost surely, 2^19850053 is an apocalyptic number.

It is an amenable number.

19850053 is a deficient number, since it is larger than the sum of its proper divisors (31515).

19850053 is an equidigital number, since it uses as much as digits as its factorization.

19850053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31514.

The product of its (nonzero) digits is 5400, while the sum is 31.

The square root of 19850053 is about 4455.3398299120. The cubic root of 19850053 is about 270.7616946197.

The spelling of 19850053 in words is "nineteen million, eight hundred fifty thousand, fifty-three".