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19914340800 = 2635219593701
BaseRepresentation
bin10010100010111111…
…001011100111000000
31220101212100022220210
4102202333023213000
5311241032401200
613052025234120
71303332050424
oct224277134700
956355308823
1019914340800
11849a142aa2
123a39332940
131b54a15713
14d6cb88b84
157b849a650
hex4a2fcb9c0

19914340800 has 336 divisors, whose sum is σ = 69958915200. Its totient is φ = 4944384000.

The previous prime is 19914340751. The next prime is 19914340807. The reversal of 19914340800 is 804341991.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19914340807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5378950 + ... + 5382650.

Almost surely, 219914340800 is an apocalyptic number.

19914340800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 19914340800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (34979457600).

19914340800 is an abundant number, since it is smaller than the sum of its proper divisors (50044574400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

19914340800 is a wasteful number, since it uses less digits than its factorization.

19914340800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3804 (or 3789 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 39.

The spelling of 19914340800 in words is "nineteen billion, nine hundred fourteen million, three hundred forty thousand, eight hundred".