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199911800000 = 265511891021
BaseRepresentation
bin1011101000101110101…
…0111111110011000000
3201010000012022122211202
42322023222333303000
511233404410100000
6231501015400332
720305000156103
oct2721352776300
9633005278752
10199911800000
1177866aaa240
12328b20830a8
1315b0bc7a623
1499664c273a
155300850dd5
hex2e8babfcc0

199911800000 has 336 divisors, whose sum is σ = 547533393120. Its totient is φ = 71808000000.

The previous prime is 199911799957. The next prime is 199911800021. The reversal of 199911800000 is 8119991.

It is a happy number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 195799490 + ... + 195800510.

It is an arithmetic number, because the mean of its divisors is an integer number (1629563670).

Almost surely, 2199911800000 is an apocalyptic number.

199911800000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 199911800000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (273766696560).

199911800000 is an abundant number, since it is smaller than the sum of its proper divisors (347621593120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

199911800000 is an equidigital number, since it uses as much as digits as its factorization.

199911800000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1158 (or 1128 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 38.

Adding to 199911800000 its reverse (8119991), we get a palindrome (199919919991).

The spelling of 199911800000 in words is "one hundred ninety-nine billion, nine hundred eleven million, eight hundred thousand".