Base | Representation |
---|---|
bin | 100110001000… |
… | …1110101000101 |
3 | 1101121220022121 |
4 | 1030101311011 |
5 | 20104332343 |
6 | 1552325541 |
7 | 331651204 |
oct | 114216505 |
9 | 41556277 |
10 | 19995973 |
11 | 103182a8 |
12 | 68438b1 |
13 | 41b164a |
14 | 292723b |
15 | 1b4eaed |
hex | 1311d45 |
19995973 has 2 divisors, whose sum is σ = 19995974. Its totient is φ = 19995972.
The previous prime is 19995967. The next prime is 19995979. The reversal of 19995973 is 37959991.
It is a balanced prime because it is at equal distance from previous prime (19995967) and next prime (19995979).
It can be written as a sum of positive squares in only one way, i.e., 16957924 + 3038049 = 4118^2 + 1743^2 .
It is a cyclic number.
It is not a de Polignac number, because 19995973 - 29 = 19995461 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 19995973.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19995979) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9997986 + 9997987.
It is an arithmetic number, because the mean of its divisors is an integer number (9997987).
Almost surely, 219995973 is an apocalyptic number.
It is an amenable number.
19995973 is a deficient number, since it is larger than the sum of its proper divisors (1).
19995973 is an equidigital number, since it uses as much as digits as its factorization.
19995973 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 688905, while the sum is 52.
The square root of 19995973 is about 4471.6857000465. The cubic root of 19995973 is about 271.4235421704.
The spelling of 19995973 in words is "nineteen million, nine hundred ninety-five thousand, nine hundred seventy-three".
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