200004112151 has 2 divisors, whose sum is σ = 200004112152. Its totient is φ = 200004112150.

The previous prime is 200004112097. The next prime is 200004112153. The reversal of 200004112151 is 151211400002.

200004112151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200004112151 is a prime.

Together with 200004112153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200004112153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100002056075 + 100002056076.

It is an arithmetic number, because the mean of its divisors is an integer number (100002056076).

Almost surely, 2^200004112151 is an apocalyptic number.

200004112151 is a deficient number, since it is larger than the sum of its proper divisors (1).

200004112151 is an equidigital number, since it uses as much as digits as its factorization.

200004112151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 17.

Adding to 200004112151 its reverse (151211400002), we get a palindrome (351215512153).

The spelling of 200004112151 in words is "two hundred billion, four million, one hundred twelve thousand, one hundred fifty-one".