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2000121112133 = 2155879277559
BaseRepresentation
bin11101000110110000100…
…000100010011001000101
321002012122212201222120122
4131012300200202121011
5230232222001042013
64130502024511325
7264334602640454
oct35066040423105
97065585658518
102000121112133
11701279252161
1228377861b545
131167c268a561
146cb409b8b9b
1537063952a08
hex1d1b0822645

2000121112133 has 4 divisors (see below), whose sum is σ = 2000130605280. Its totient is φ = 2000111618988.

The previous prime is 2000121112103. The next prime is 2000121112159. The reversal of 2000121112133 is 3312111210002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2000121112133 - 234 = 1982941242949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000121112103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4423193 + ... + 4854366.

It is an arithmetic number, because the mean of its divisors is an integer number (500032651320).

Almost surely, 22000121112133 is an apocalyptic number.

It is an amenable number.

2000121112133 is a deficient number, since it is larger than the sum of its proper divisors (9493147).

2000121112133 is an equidigital number, since it uses as much as digits as its factorization.

2000121112133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9493146.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 2000121112133 its reverse (3312111210002), we get a palindrome (5312232322135).

The spelling of 2000121112133 in words is "two trillion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 215587 9277559 2000121112133